3x^2-15x-5400=0

Solution for 3x^2-15x-5400=0 equation:

3x^2-15x-5400=0

a = 3; b = -15; c = -5400;
Δ = b2-4ac
Δ = -152-4·3·(-5400)
Δ = 65025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65025}=255$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-255}{2*3}=\frac{-240}{6}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+255}{2*3}=\frac{270}{6}
=45
$